(2 + 3i)/(3 -3i) = [(2 + 3i)/(3 -3
i)] ● [(3+3i)/(3+3i)]
=(6 + 6i + 9i + 9i2)/(9 +9i-9i - 9i2)
= (6 + 6i + 9i - 9)/(9 +9i-9i +9)
= (-3 + 15i)/18
= -3/18 + (15/18)i
|
Given
___________________________________
___________________________________
___________________________________
___________________________________
___________________________________
|