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Linear Inequalities - Exercise 3

Find the critical numbers of the inequality given below by solving |2x - 3| =  1. Then test intervals and find the solution interval or intervals. The Justification has been given - No further justification is needed.
 

STATEMENT JUSTIFICATION
|2x - 3| ≥  1
|2x - 3| =  1 is related equation

 

 

 

 

 

 

 

 

 

 

 

 Given

Use the Division and Addition Properties of Equality to solve each case of the absolute value equation and find critical numbers.

Use the property: Critical Numbers Define Solution Interval Endpoints to test and determine solutions.

 
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